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=-5P^2+60P-135
We move all terms to the left:
-(-5P^2+60P-135)=0
We get rid of parentheses
5P^2-60P+135=0
a = 5; b = -60; c = +135;
Δ = b2-4ac
Δ = -602-4·5·135
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30}{2*5}=\frac{30}{10} =3 $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30}{2*5}=\frac{90}{10} =9 $
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